3.5.30 \(\int \frac {1}{\sqrt {1-a^2 x^2} \text {ArcSin}(a x)^3} \, dx\) [430]

Optimal. Leaf size=13 \[ -\frac {1}{2 a \text {ArcSin}(a x)^2} \]

[Out]

-1/2/a/arcsin(a*x)^2

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Rubi [A]
time = 0.02, antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {4737} \begin {gather*} -\frac {1}{2 a \text {ArcSin}(a x)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[1 - a^2*x^2]*ArcSin[a*x]^3),x]

[Out]

-1/2*1/(a*ArcSin[a*x]^2)

Rule 4737

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(1/(b*c*(n + 1)))*Si
mp[Sqrt[1 - c^2*x^2]/Sqrt[d + e*x^2]]*(a + b*ArcSin[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c
^2*d + e, 0] && NeQ[n, -1]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {1-a^2 x^2} \sin ^{-1}(a x)^3} \, dx &=-\frac {1}{2 a \sin ^{-1}(a x)^2}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 13, normalized size = 1.00 \begin {gather*} -\frac {1}{2 a \text {ArcSin}(a x)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[1 - a^2*x^2]*ArcSin[a*x]^3),x]

[Out]

-1/2*1/(a*ArcSin[a*x]^2)

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Maple [A]
time = 0.10, size = 12, normalized size = 0.92

method	result	size
derivativedivides	\(-\frac {1}{2 a \arcsin \left (a x \right )^{2}}\)	\(12\)
default	\(-\frac {1}{2 a \arcsin \left (a x \right )^{2}}\)	\(12\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/arcsin(a*x)^3/(-a^2*x^2+1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/2/a/arcsin(a*x)^2

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Maxima [A]
time = 0.47, size = 11, normalized size = 0.85 \begin {gather*} -\frac {1}{2 \, a \arcsin \left (a x\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsin(a*x)^3/(-a^2*x^2+1)^(1/2),x, algorithm="maxima")

[Out]

-1/2/(a*arcsin(a*x)^2)

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Fricas [A]
time = 1.65, size = 11, normalized size = 0.85 \begin {gather*} -\frac {1}{2 \, a \arcsin \left (a x\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsin(a*x)^3/(-a^2*x^2+1)^(1/2),x, algorithm="fricas")

[Out]

-1/2/(a*arcsin(a*x)^2)

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Sympy [A]
time = 0.40, size = 12, normalized size = 0.92 \begin {gather*} - \frac {1}{2 a \operatorname {asin}^{2}{\left (a x \right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/asin(a*x)**3/(-a**2*x**2+1)**(1/2),x)

[Out]

-1/(2*a*asin(a*x)**2)

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Giac [A]
time = 0.45, size = 11, normalized size = 0.85 \begin {gather*} -\frac {1}{2 \, a \arcsin \left (a x\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsin(a*x)^3/(-a^2*x^2+1)^(1/2),x, algorithm="giac")

[Out]

-1/2/(a*arcsin(a*x)^2)

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Mupad [B]
time = 0.12, size = 11, normalized size = 0.85 \begin {gather*} -\frac {1}{2\,a\,{\mathrm {asin}\left (a\,x\right )}^2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(asin(a*x)^3*(1 - a^2*x^2)^(1/2)),x)

[Out]

-1/(2*a*asin(a*x)^2)

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